Chapter 8-4 Déjà
vu Foil the following:
(a +3)2 ( which is called a binomial squared)
(a + 3)(a +3) = a2 + 3a + 3a + 9 = a2 + 6a + 9 ( called a trinomial square)
(a + 3)(a +3) = a2 + 3a + 3a + 9 = a2 + 6a + 9 ( called a trinomial square)
Again, you see that the middle term is DOUBLE the product of
the two terms in the binomial
and the first and last terms are simply the squares of each term in the binomial
and the first and last terms are simply the squares of each term in the binomial
How to recognize that it is a Binomial Squared:
1)
Is it a trinomial? ( if it’s a binomial it cannot be a binomial squared)
2) Are the first and last terms POSITIVE?
3) Are the first and last terms PERFECTSQUARES?
4) Is the middle term DOUBLE the product of the SQRTS of the 1st and last terms?
2) Are the first and last terms POSITIVE?
3) Are the first and last terms PERFECTSQUARES?
4) Is the middle term DOUBLE the product of the SQRTS of the 1st and last terms?
To FACTOR a Trinomial Square
a2 + 6a + 9 (called a trinomial square)
a2 + 6a + 9 (called a trinomial square)
1)
Put ONE set of {{HUGS} with an exponent of 2
( )2
2) Put the sign of the middle term inside (in this case its +) ( + )2
3) Find the SQRT’s of the first term & last terms; place them in parentheses (a +3)2
4) Check by FOILing back
2) Put the sign of the middle term inside (in this case its +) ( + )2
3) Find the SQRT’s of the first term & last terms; place them in parentheses (a +3)2
4) Check by FOILing back
If the sign is
negative in the middle, simple use a negative sign when you factor.
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