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Wednesday, December 9, 2009

Math 6H ( Periods 3, 6, & 7)

Greatest Common Factor 5-5

Also check out December 1, 2009 posting of GCF. Here is a review of that lesson...


When the factors in the numbers 30 and 42 are listed, the numbers 1, 2, 3, and 6 appear in both lists
Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30
Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42

These numbers are called common factors of 30 and 42. The number 6 is the greatest of these numbers and is therefore called the greatest common factor of the two numbers.
We write
GCF(30,42) = 6
to denote the greatest common factor of 30 and 42

Find GCF(54, 72)
List the factors of each number

54: 1, 2, 3, 6, 9, 18, 27, 54
Factors of 72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

the common factors are 1, 2, 3, 6, 9, and 18

the greatest number in both lists is 18. Therefore,

GCF(54, 72) = 18

Another way to find the GCF of two numbers is to use prime factorization.
Find GCF (54, 72)
First find the prime factorization of 54 and of 75

54 = 2∙3∙3∙3∙3
72 = 2∙2∙2∙3∙3

Find the greatest power of 2 that occurs in both prime factorization. 2
Find the greatest power of 3 that occurs in both prime factorization 32
Therefore GCF(54,72) = 2∙32 = 18

Try GCF(45, 60) using the prime factorization method

The number 1 is a common factor of any two whole numbers.
If 1 is the GCF, then the two numbers are said to be relatively prime.
Show that 15 and 16 are relatively prime
List the factors of each number
Factors of 15 = 1, 3, 5, 15
Factors of 16: 1, 2, 4, 8, 16
Since the GCF(15, 16) = 1, the two numbers are relatively prime

Pre Algebra Period 1

Simplifying Fractions 4-4

Equivalent Fractions - Just multiply the numerator and the denominator by the same number and you will get an equivalent (equal) fraction to the one you started with.


GOLDEN RULE OF FRACTIONS = Do unto the numerator as you do unto the denominator


Simplifying fractions (your parents call this "reducing")

2 good ways:

(1) Just divide both the numerator and denominator by the GCF

(2) Another way: Rewrite the numerator and denominator in prime factorization form. Then simply cross out each common factor on the top and bottom
(they cross out because it's 1)

You'll be left with the simplified fraction every time!!!!
                                           


THE GCF METHOD:

One of the reasons we learn the GCF is because it's the FASTEST WAY TO SIMPLIFY FRACTIONS IN ONE STEP!!!

Just divide both the numerator and denominator by the GCF

THE PROBLEM WITH THE METHOD:
If you're not comfortable finding the GCF, you're pretty much sunk with this method! :(

THE BEST REASON TO USE THIS METHOD (other than it's a Calif. STAR Key Standard), it truly is the FASTEST :)

So imagine you have a "GCF Magical Voice" in your head...
The voice tells you the GCF of the numerator and the denominator...
You simply use that GCF to divide both the top and bottom of your fraction and you're done in one step!



THE PRIME FACTORIZATION METHOD:

This is sort of using the GCF "incognito" (in disguise)!

Rewrite the numerator and denominator in prime factorization form.

(Use a Factor Tree or Inverted Division to find the Prime Factorization if necessary).

Then simply cross out each common factor on the top and bottom.

(You're actually using the ID Property of Multiplication because 
each "crossout" is really a quotient of 1!)

You'll be left with the simplified fraction every time!!!!

If you actually multiplied together all your cross-outs, you'd get the GCF...
so you're using the GCF without even computing it!

THE PROBLEM WITH THIS METHOD:
You may think it's a lot of work


THE BEST REASON TO USE THIS METHOD: Although it takes time, everyone can do a Factor Tree or Inverted Division and create the Prime Factorization...
You'll never get the wrong answer with this one!



THE CROSS OUT METHOD:

You simply think of the first number that comes to your mind that "goz-into" both the numerator and the denominator and keep going until it's simplified.

If it's even, most people start with dividing it in half....and then in half again, etc.

This probably takes the longest, but in practice, most people use this method!

THE PROBLEM WITH THIS METHOD: You may think that a fraction is simplified, but you've missed a factor...this especially happens when the number is odd and you're always used to using 2 to divide the top and the bottom!

THE BEST REASON TO USE THIS METHOD: No one ever forgets how to do this method...it just comes naturally and there are no "precise" steps to do!
 
EXAMPLE: Simplify by each method:
36/
54
 
GCF METHOD:

The GCF is 18:

36 ÷ 18 = 2

54 ÷ 18 = 3



PRIME FACTORIZATION METHOD:

36 = 2 x 2 x 3 x 3

54 = 2 x 3 x 3 x 3

Two of the 3s cross out and one of the 2s

You are now left with:

2/
3

That's it!!!!!!!!!



CROSS OUT METHOD:
36 ÷ 2 = 18 ÷ 3 = 6 ÷ 3 = 2

54 ÷ 2 = 27 ÷ 3 = 9 ÷ 3 = 3


so 36/54 = 2/3
Do the same thing with variables!

Algebra Period 4

Difference of Two Squares 6-2

Again, remember that FACTORING just UNDOES multiplication.

In this case, the multiplication that you'll be UNDOING is FOILING.

FOIL:
(a + b)(a - b)

You will get:
a2 - b2
This is the DIFFERENCE (subtraction) of TWO SQUARES.

Now FACTOR:
a2 - b2
You undo the FOILING and get:
(a + b)(a - b)


REMEMBER:
You must have two different signs because that's how the MIDDLE TERM disappears!

You will get ADDITIVE INVERSES which will become ZERO



HOW TO RECOGNIZE THE DIFFERENCE OF TWO SQUARES:

1) Is it a binomial?

2) Is it a difference?

3) Are both terms perfect squares?


IF YES TO ALL 3 QUESTIONS, THEN YOU HAVE A DIFFERENCE OF 2 SQUARES!!

HOW TO FACTOR THE DIFFERENCE OF 2 SQUARES:

1) Double hug  (    )(    )

2) Find square root of each term (sq rt sqrt)(sq rt sq rt)

3) Make one sign positive and one sign negative.
              
(sq rt + sqrt)(sq rt -sq rt)


                           
Of course, they get more complicated! 
We can combine pulling out the GCF with this!

ALWAYS LOOK FOR A GCF TO PULL OUT FIRST!!!!!!

EXAMPLE:

27y2 - 48y4
First, look for a GCF that can be pulled out.

The GCF = 3y2

Factor out the GCF (look at Chapter 6-1):
3y2(9 - 16y2 )
NOW YOU HAVE A DIFFERENCE OF TWO SQUARES TO FACTOR:


3y2(3 - 4y)(3 + 4y)


CALLED FACTORING COMPLETELY BECAUSE
 YOU CANNOT FACTOR FURTHER!


Always check your factoring by distributing or FOILing back!


THERE IS NO SUCH THING AS THE SUM OF TWO SQUARES!

a2 + b2 CANNOT BE FACTORED!!!!!


BUT - b2 + a2
= + a2 -b2
= (a + b)(a - b)
BECAUSE IT'S JUST SWITCHED (COMMUTATIVE)

Tuesday, December 8, 2009

Algebra Period 4

Factoring Polynomials 6-1

Chapter 5 was a very important chapter that you cannot survive without...

CHAPTER 6 IS EVEN MORE IMPORTANT FOR HIGH SCHOOL!!!



As I stated-- these chapters are the Meat & Potatoes of Algebra!!

REMEMBER:

FACTORING WILL NEVER CHANGE THE ORIGINAL VALUE OF THE POLYNOMIAL SO YOU SHOULD ALWAYS CHECK BY MULTIPLYING BACK!!!!
(You'll either distribute or FOIL...that's what you learned how to do in Chapter 5!)


CHAPTER 6-1: FACTORING THE GCF

Factoring is a skill that you must understand to be successful in higher level math!!!

We did a simple version of this back in Chapter 1!


Factoring is simply UNDOING multiplying

Say you multiplied 5 by 10 and got 50

How would you undo it?
DIVIDE by 5!

So FACTORING uses the concept of DIVIDING.

You're actually undoing the DISTRIBUTIVE PROPERTY.

How?

You look for the most of every common factor....the GCF!

Then you pull out the GCF (divide it out of) from each term, 
Placing the GCF in front of ( )


EXAMPLE:

FIRST,
DISTRIBUTE:

2m2n(2n2 + n + 3)


4m2 n3 + 2m2 n2 + 6m2 n



Now, pretend you don't want the 2m2n distributed anymore...
What should you end up with once you UNDO the Distributive Property?

2m2 n (2n2 + n + 3)



That's exactly what you started with!

So is it that easy?

Well yes... and no...

Yes because that is the answer
 and

No because it was only that easy because I gave you how it started!

You won't know how it started in a real problem!
THIS IS AN EXAMPLE THE WAY YOU WOULD USUALLY SEE IT.

The question would say:
FACTOR: 
4m2 n3 + 2m2 n2 + 6m2 n



Step 1: What does each term have in common (what is the GCF) ?

They each can be divided by 2m2 n


Step 2: Put the GCF in front of a set of (   ) and divide each term by the GCF
2m2 n [ (4m2 n3)/2m2 n + (2m2 n2)/2m2 n + (6m2n/2m2 n]

Step 3: SIMPLIFY and you'll get:

2m2n (2n2 + n + 3)



Step 4: Check your answer!!!!!

Always check your factoring of the GCF by distributing back!

(incognito, it should be the same thing)



RELATIVELY PRIME TERMS ARE 
TERMS WITH NO COMMON FACTORS
 THAT MEANS THAT THEY CANNOT BE FACTORED (GCF = 1)
We say they are "not factorable"


Monday, December 7, 2009

Math 6H ( Periods 3, 6, & 7)

Prime Numbers and Composite Numbers 5-4

A prime number is a positive integer greater than 1 with exactly two factors, 1 and the number itself. The numbers 2, 3, 5, 7 are examples of prime numbers

A composite number is a positive integer greater than 1 with more than two factors. The numbers 4, 6, 8, 9, and 10 are examples of composite numbers.

Since 1 has exactly 1 factor, it is neither prime nor composite.

About 230 BCE Erathosthenes, a Greek Mathematician suggested a way to find prime numbers—up to a specific number. The method is called the Sieve of Eratosthenes because it picks out the prime numbers as a strainer, or sieve, picks out solid particles from a liquid.

You may factor a number into prime factors by using either of the following methods
➢ Inverted short division
➢ Factor tree

Both were shown in class.

Could you start the factor tree differently? If so, would you end up with the same answer?


The prime factors of 42 are the same in either factor tree, except for their order.

Every composite number greater than 1 can be written as a product of prime factors in exactly one way, except for the order of the factors.

When we write 42 as 2 ∙ 3 ∙ 7 this product is called the prime factorization of 42

Notice the order in which prime factorization is written.

Let’s try finding the prime factorization of 60

The prime factorization of 60 = 2 ∙ 2∙ 3 ∙ 5 or 22∙ 3∙ 5

Pre Algebra Period 1

Prime Factorization & GCF 4-3
Greatest Common Factor - think of it backwards to understand it!

Factor = must be a number that goes into the numbers

Common = must be a number that goes into BOTH the numbers

Greatest = must be the biggest number that goes into BOTH the numbers

There are several ways to find it.

1) List all the factors of each number and circle the biggest one that is common to both
 (takes too long!!)
2) Circle the common factors in the prime factorizations of each number and multiply

3) list the factors in a table and bring down the factors whose column is filled.
Then multiply.


EXAMPLE:
Find the GCF of 36, 45 and 54


LIST ALL THE FACTORS OF EACH NUMBER:

1, 2, 3, 4, 6, 9, 12, 18, 36

1, 3, 5, 9, 15, 45

1, 2, 3, 6, 9, 18, 27, 54

The GCF is 9


FIND THE PRIME FACTORIZATIONS ON A FACTOR TREE OR INVERTED DIVISION AND MULTIPLY THE COMMON FACTORS:

36 = 2 x 2 x 3 x 3

45 = 3 x 3 x 5

54 = 2 x 3 x 3 x 3

GCF = 3 x 3 = 9

PUT THE PRIME FACTORIZATIONS IN A BOX WITH COLUMNS:
   as shown in class                                     

DO THE SAME THING WITH VARIABLES:
The GCF of the variables is the most of each variable that each term has in common.
EXAMPLE:
Find the GCF of a2b3c4   ac3d   a3c2f
The COMMON variables are a and c
How many of each variable is COMMON to all 3 terms:
They each have 1 a (although the first term has 2 and the 3rd term has 3)
They each have 2 c's (although the 1st term has 4 and the 2nd has 3)
GCF = ac2
Again, the GCF of variables is simply the lowest power of common variables
You should look for a special case of GCFs:
When one number goes into the other number(s), the smaller number is always the GCF.
Example: The GCF of 50 and 100 is 50
50 is the biggest factor that goes into both 50 and 100!

Friday, December 4, 2009

Math 6H ( Periods 3, 6, & 7)

Square Numbers & Square Roots (Continued) 5-3

Before we began---We reviewed the terminology for various numbers using 75 as our example
75---the standard form of the number
3⋅ 5⋅ 5 is it written in expanded prime factorization
3⋅ 52 is it's exponential prime factorization

If you have a prime number all three are exactly the same
For example
41 --- is the standard form of the number
but 41 is also the expanded prime factorization
and 41 ( or 411) is it written in exponential prime factorization.
[You can leave off the exponent 1 for the power of 1 because it is truly invisible!!]


Knowing the SQ's & SQRT's of numbers up to 20 is critical for finding the approximate square root of any non perfect square.
That is,
You know the √36 = 6
and √25 = 5
But what would be
√28 ?

There are several strategies to use.. one involved dividing and taking the average. This is from the yellow worksheet handed out on Friday 12/4
You know that √28 is less than 6 but more than 5
so you start with 5
divide 28 by 5
28 ÷ 5 = 5.6
Now take the average of 5 and 5.6 or
5 + 5.6
2

which equals 5.3

Divide 28 by 5.3 now
28 ÷ 5.3 = equals 5.28 or rounded 5.3
Since the divisor (5.3) and the quotient (5.3) match STOP...and say

√28≈ 5.3

That's fairly complicated... in class we showed some neat tricks about the relationship between the perfect squares...
Using the same number √28

You still think of the perfect square below and above

Stack them
36
√28
25

then take the square roots for those perfect squares

√36 = 6
√28 ≈
√25 = 5

√36 = 6
√28 ≈ 5
√25 = 5

Now, find the difference between your two perfect squares
36 -25 = 11
We discovered that the difference will always be the sum of the square roots of the perfect squares!! WOW!!

That number becomes your denominator

Now, find the difference between your number (in this case 28) and the lower of the two perfect squares (25) so 28-25 = 3
That number becomes the numerator
so you have

3/11

Now, we haven't learned about fractions but you can estimate ( since this is all about estimating... anyway)
and you know

3/10
That can be written as .3
so adding that to your estimate
we can safely estimate
√28 ≈ 5.3

Try finding the √110... with this method..

Math 6H ( Periods 3, 6, & 7)

Least Common Multiple 5-6

We looked at the first few non-zero multiples of 8 and 12
Multiples of 8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80...
Multiples of 12: 12, 24, 36, 48, 60, 72, 84 ...

We noticed 24, 48, and 72 appear in both lists. These numbers are called common multiples of 8 and 12 and the LEAST of the multiples is 24...
It is called... the least common multiple.
We write the least common multiple of 8 and 12 as
LCM(8,12) = 24

To find the LCM of two whole numbers you could write out the lists of multiples-- and that works relatively easily with small numbers... but there are more efficient ways to find the least common multiple of two whole numbers.

1. Write out the first few multiples of the larger of the two numbers and test each multiple for divisibility by the smaller number. The first multiple of the larger number that is divisible by the smaller number is the LCM

2. You can use prime factorization to find the LCM. The LCM is EVERY factor to its GREATEST power!!

LCM(54, 60)
54 = 2⋅ 3⋅ 3⋅ 3 = 2⋅ 33
60 = 2⋅ 2⋅ 3⋅ 5 = 22⋅ 3⋅ 5
So the greatest power of 2 is 22
The greatest power of 3 is just 3
and the greatest pwoer of 5 is just 5
so the product of 22⋅ 3⋅ 5 will be the LCM
LCM(54, 60) = 540

3. You may use the BOX method as shown in class... unfortunately it does not show well here. Remember you need to create a L. The numbers on the side of the box represent the GCF!! You need to multiple them with the last row of factors.
See me before or after class if you want any review!!


We reviewed the concept of relatively prime and noticed that any two prime numbers are relatively prime. We also noticed that if two numbers are relatively prime-- neither of them must be prime....

We also found out that if one number is a factor of a second number, the GCF of the two numbers is the first number AND... if one whole number is a factor of a second whole number the LCM of the two numbers is the second number!!
GCF(12,24) = 12
LCM(12,24) = 24

WOW!!

If two whole numbers are relatively prime---
their GCF = 1
and their LCM is their product!!
GCF(8,9) =1
GCF(8,9) = 72

WOW!!

LCM & GCF Story PRoblems
1) Read the problem
2) Re-read the problem!!
3) Figure out what is being asked for!!
4) find the "magic " word... to help you determine if you are finding GCF or LCM
5) When in doubt... draw it out!!

Tuesday, December 1, 2009

Algebra Period 4

Multiplying Polynomials 5-11

To multiply two polynomials, multiply each term of one polynomial by every term of the other. THEN ADD the results.

The textbook shows a column approach, please see page 249 for instructions.
In class we used the BOX method... and then combined terms.

When you multiply a trinomial by a binomial or two trinomials, it gets really tricky!


2 ways:

1) box method

2)column method
(double or triple distributive with columns to combine like terms)




If you have a trinomial times a binomial, it's easier to use the Commutative Property

and make it a binomial times a trinomial:

(x2 + x - 1) (x - 1)

switch it to

(x - 1) (x2 + x - 1)

Remember the following rules
(A + B)(A + B) = (A + B) 2 = A2 + 2AB + B2

(A - B)(A - B) = (A - B)2 = A2 -2AB + B2

(A + B)(A - B)= A2- B2
You can use FOIL to multiply two binomials
remember FOIL is First Terms, Outside Terms, Inside Terms, Last Terms

You can always use FOIL-- or the BOX method but knowing these rules will make computation quicker if you know the above rules!!

Math 6H ( Periods 3, 6, & 7)

Greatest Common Factor 5-5

If we list the factors of 30 and 42, we notice
Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30
Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42

We notice that 1, 2, 3, and 6 are all COMMON factors of these two numbers. The number 6 is the greatest of these and therefore is called the
GREATEST COMMON FACTOR of the two numbers. We write
GCF(30,42) = 6

Although listing the factors of two numbers and then comparing their common factors is one way to determine the greatest common factor, using prime factorization is another easy way to find the GCF

Find GCF(54, 72)
54 = 2 ⋅ 3 ⋅ 3 ⋅ 3
72 = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 3
Find the greatest power of 2 that occurs IN BOTH prime factorization. The greatest power of 2 that occurs in both is just 2 1
Find the greatest power of 3 that occurs IN BOTH prime factorizations. The greatest power of 3 that occurs in both is 32
Therefore
GCF(54, 72) = 2 ⋅ 32 = 18

In class we circled the common factors and realized that
GCF(54, 72) = 2 ⋅ 3 ⋅ 3 = 18


Fin the GCF( 45, 60)
45 = 3 ⋅ 3⋅ 5
60 = 2⋅ 2⋅ 3⋅ 5
Since 2 is NOT a factor of 45-- there is NO greatest power of 2 that occurs in both prime factorizations.
The greatest power of 3 is just 31
and the greatest power of 5 is just 51
Therefore,
GCF(45,60) = 3⋅ 5 = 15

The number 1 is a common factor of any two whole numbers!! If 1 is the GCF , then the two numbers are said to be RELATIVELY PRIME. Two numbers can be relatively prime even if one or both of them are composite.

Show that 15 and 16 are relatively prime
List the factors of each number
FACTORS of 15: 1, 3, 5, 15
FACTORS of 16: 1, 2, 4, 8, 16

Since the GCF(15,16) = 1. The two numbers are relatively prime!!

Monday, November 30, 2009

Math 6H ( Periods 3, 6, & 7)

Prime Numbers & Composite Numbers 5-4

A prime number is one that has only two factors: 1 and the number itself, such as 2, 3, 5, 7, 11, 13...
A counting number that has more than two factors is called a composite number, such as 4, 6, 8, 9, 10...

Since one has exactly ONE factor, it is NEITHER PRIME NOR COMPOSITE!!
Zero is also NEITHER PRIME NOR COMPOSITE!!

Every counting number greater than 1 has at least one prime factor -- which may be the number itself.
You can factor a number into PRIME FACTORS by using a factor tree or the inverted division, as shown in class.

Using the inverted division, you also start with the smallest prime number that is a factor... and work down
give the prime factors of 42
2⎣42
3⎣21
7

When we write 42 as 2⋅3⋅7 this product of prime factors is called the prime factorization of 42.

Two is the only even prime number because all the other even numbers have two as a factor.

Explain how you know that each of the following numbers must be composite...
111; 111,111; 111,111,111; and so on....
Using your divisibility rules you notice that the sums of the digits are multiples of 3.

List all the possible digits that can be the last digit of a prime number that is greater than 10.
1, 3, 7, 9.

Choose any six digit number such that the last three digits are a repeat of the first three digits. For example
652,652. You will find that 7, 11, and 13 are all factors of that number... no matter what number you choose... why is that???? email me your response.

Algebra Period 4

Multiplying Binomials: Special Products 5-10

LEARN TO RECOGNIZE SOME SPECIAL PRODUCTS - IT MAKES IT EASIER!


Remember: You can FOIL these just like the other products until you remember these special patterns....but when we get to factoring next week, it will really help you to know these patterns by heart. 

When you do, you actually don't need to show any work because you do it in your head! 

(That should make a lot of you happy! :)



DIFFERENCE OF TWO SQUARES:

You will notice that the two factors are IDENTICAL except they have DIFFERENT SIGNS

(x + 6)(x - 6) =
x2 - 6x + 6x - 36 =
x2 - 36


This will happen every time!
 
The middle terms are additive inverses so they become zero.


You're left with a difference (subtraction) of two terms that are squared.



SQUARING A BINOMIAL:

When you multiply one binomial by itself (squaring it), you end up with:

First term squared + twice the product of both terms + last term squared


(x + 6)2 =
(x + 6)(x + 6) =
x2 + 2(6x) + 62 =
x2 + 12x + 36


If you foiled you would have:

x2  + 6x + 6x + 36


CAN YOU SEE THAT THE 2 MIDDLE TERMS ARE JUST DOUBLING UP??? 

WHY???


Another example with subtraction in the middle:

(x - 6)2 =
(x - 6)(x - 6) =
x2 + 2(-6x) + 62 =
x2 - 12x + 36


If you foiled you would have:

x2 - 6x - 6x + 36


CAN YOU SEE THAT THE 2 MIDDLE TERMS ARE JUST DOUBLING UP??? 
WHY???



PLEASE NOTE:

NOTICING THESE SPECIAL PRODUCTS HELPS YOU DO THESE 
MULTIPLICATIONS FASTER!

IF YOU EVER FORGET THEM, JUST FOIL!


(but you will need to recognize them for factoring in Chapter 6)

Thursday, November 19, 2009

Math 6H ( Periods 3, 6, & 7)

Square Numbers and Square Roots 5-3

Numbers such as 1, 4, 9, 16, 25, 36, 49... are called square numbers or PERFECT SQUARES.

One of two EQUAL factors of a square is called the square root of the number. To denote a square root of a number we use a radical sign (looks like a check mark with an extension) See our textbook page 157.

Although we use a radical sign to denote cube roots, fourth roots and more, without a small number on the radical sign, we have come to call that the square root.
SQRT = stands for square root, since this blog will not let me use the proper symbol) √ is the closest to the symbol

so the SQRT of 25 is 5. Actually 5 is the principal square root. Since 5 X 5 = 25
There is another root because
(-5)(-5) = 25 but in this class we are primarily interested in the principal square root or the positive square root.

Evaluate the following:
SQRT 36 + SQRT 64 = 6 + 8 = 14
SQRT 100 = 10
Is it true that SQRT 36 + SQRT 64 = SQRT 100? No
You cannot add square roots in that manner.
However look at the following:
Evaluate
SQRT 225 = 15
(SQRT 9)(SQRT 25)= (3)(5) = 15
so
SQRT 225 = (SQRT 9)(SQRT 25)

Also notice that the SQRT 1600 = 40
But notice that SQRT 1600 = SQRT (16)(100) = 4(10) = 40

Try this:
Take an odd perfect square, such as 9. Square the largest whole number that is less than half of it. ( For 9 this would be 4). If you add this square to the original number what kind of number do you get? Try it with other odd perfect squares...

In this case, 9 + 16 = 25... hmmm... what's 25???

Wednesday, November 18, 2009

Math 6H ( Periods 3, 6, & 7)

Tests for Divisibility 5-2

It is important to learn the following divisibility rules:
A number is divisibility by:

2 ... if the ones digit of the number is even
3 ... if the sum of the digits is divisible by three ( add the digits together)
4 ... if the number formed by the last two digits is divisible by by four ( Just LOOK at the last two numbers-- DON"T ADD them!!)
5 ... if the ones digits of the number is a 5 or a 0
6 ... if the number is divisible by both 2 and 3... (or if it is even and divisible by 3)
8 ... if the number formed by the last three digits is divisible by 8. (Like FOUR, just look at the last three digits-- divide them by 8)
9 ... if the sum of the digits is divisible by 9
10 ... if the ones digits of the number is a 0.

You will not need to know the divisibility rules for 7 or 11 but they are interesting...

You can test for divisibility by 7
Let's start with a number 959
Step 1: drop the one's digit so we have 95
Step 2: Subtract twice the ones' digit ( that you dropped) in this case we dropped a 9
so we double that and subtract 18 from 95
or 95-18 = 77. If the results, in the case, 77, is divisible by 7 --- so is the original number 959.
Step 3: If the number you get is still to big.. continue the process until you can determine if your number is divisible by 7.


To test for divisibility by 11
add the alternative digits beginning with the first
so let's try the following
4,378,396
Step 1: Add the alternate digits beginning with the 1st 4 + 7+ 3 + 6 = 20
Step 2: Add alternate digits beginning with the 2nd 3 + 8 + 9 = 20

Step 3: If the difference of the sums is divisible by 11 so is the original number.
In this case, 20-20 = 0 and 0/11= 0 so
4,378,396 is divisible by 11.


A good test for divisibility by 25 would be if the last two digits represent a multiple of 25.

A perfect number is one that is the SUM of all its factors except itself. The smallest perfect number is 6, since 6 = 1 + 2+ 3
The next perfect number is 28 since
28 = 1 + 2 + 4 + 7 + 14
What is the next perfect number?