Using Addition to Solve a System
6-3
The second
Algebraic method to solve a system is known as ELIMINATION.
You’ll be
eliminating one variable by using the ADDITIVE INVERSE of it in the other
equation.
Example where you
add the two equations together:
4x + 6y = 32
3x – 6y = 3
--------------------
7x + 0 = 35
x = 5
Plug into either
equation to find y:
4(5) + 6y = 32
20 + 6y = 32
6y = 12
y = 2
The solution is
(5, 2)
Sometimes you’ll
ALMOST have additive inverses, but you’ll need to multiply one equation by -1
first:
5x + 2y = 6
9x + 2y = 22
--------------------
Multiply either
the top or bottom by -1 (your choice):
5x + 2y
= 6
-9x - 2y = -22
--------------------
-4x + 0 = -16
x = 4
Plug into either
ORIGINAL equation:
5(4) + 2y = 6
20 + 2y = 6
2y = -14
y = -7
The solution is
(4, -7)
Now you can plug
this point into the other equation to check that you haven’t made a mistake:
9x + 2y = 22
9(4) + 2(-7) = 22
36 – 14 = 22
22 = 22
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