Chapter 3-4 Direct Variation
We’ve learned that
the unit rate is the constant rate of change in a linear relationship and that
it’s the slope of a line when it’s graphed. We’ve also learned that if a graph
of an equation goes through the origin
(0,0) it’s proportional and the ratio of any y value to it’s x value
is a constant (which turns out to be the unit
rate or constant rate of change or slope
of the line)
When the linear
relationship is proportional, we say it’s a DIRECT VARIATION.
Now the constant rate of change, the slope, the unit rate, is called the CONSTANT OF VARIATION or the CONSTANT OF PROPORTIONALITY
This is not a new concept. IT IS just NEW VOCAB!
This is not a new concept. IT IS just NEW VOCAB!
We also say: y varies directly (constantly) with x.
The slope is now
replaced by the letter k instead of m
Finding the equation
of a line that is proportional
Find k (the slope)
by counting the rise/run of the graph
Write the equation
using the format y = kx
Notice: if you
always pick the origin as the point to count rise/run from—the slope (k) is
always just y/x
In a word problem,
if it says one amount VARIES DIRECTLY with another, you know that the origin is
one of the points!!
You also know that
the equation is y = kx
YOU just need to find k
and k is y/x of any point OTHER THAN THE ORIGIN
YOU just need to find k
and k is y/x of any point OTHER THAN THE ORIGIN
A babysitting example
The amount of
money earned VARIES DIRECTLY with the
time worked.
THINK: the graph and equation go through (0,0)
THINK: Any other point will give you the slope,
or constant of proportionality, or unit rate ( all the same thing) SO you only
need one additional point.
We are given that
she earns $30 for 4 hours. Find the equation.
Rise/Run = y/x
BECAUSE THEY SAID IT VARIED DIRECTLY!!
BECAUSE THEY SAID IT VARIED DIRECTLY!!
k = 30/4
Simplify
k = 7.5
So the equation is y = 7.5x
Simplify
k = 7.5
So the equation is y = 7.5x
What does the 7.5
represent?
The unit rate of $7.50/ hour of babysitting!
The unit rate of $7.50/ hour of babysitting!
A bicycling example
The distance the cyclist bikes in miles VARIES DIRECTLY with the time in hours that he bikes.
The distance the cyclist bikes in miles VARIES DIRECTLY with the time in hours that he bikes.
THINK: The graph and equation go through the
origin (0,0).
THINK: Any other point will give you the slope, or constant of proportionality, or unit rate (all the same thing) SO you only need one additional point.
THINK: Any other point will give you the slope, or constant of proportionality, or unit rate (all the same thing) SO you only need one additional point.
He bikes 3 miles
in ¼ hour. Find the equation.
Rise/run = y/x
BECAUSE THEY SAID IT VARIES DIRECTLY
BECAUSE THEY SAID IT VARIES DIRECTLY
k = 3/¼ or 3/.25 Now the hardest part is doing this
3/.25
If you kept it as
3/¼ you could read this as 3 divided by
¼
THINK: instead of dividing, multiply by the reciprocal of ¼
THINK: instead of dividing, multiply by the reciprocal of ¼
or 3 (4/1) = 12
(Wait, wasn’t that much easier than dividing 3 by .25!!
k = 12
k = 12
The equation is y
= 12x
What does the 12
represent?
The unit rate of
12 miles/ hour – that’s the cyclist’s speed 12mph
Determining whether a Table of Values is Direct
Variation If you are given a table of
values, you can determine if the relationship is direct variation by dividing 3
y’s by their x values and making sure that you get the SAME
value. If you do, it is
proportional, goes through the
origin (0,0) and the slope of y/x is the unit rate ( which is now called the constant of variation)!
Example
Given 3 points (5,
20) , (6, 24), and (7, 28):
Divide
each y/x
20/5
= 4
24/6
= 4
28/7
= 4
Since all the
ratios simplify to the same value (4), it is a direct variation. The slope of 4
is the unit rate, which is the constant rate of change and is now also called
the constant of variation.
Finding Additional
Values for the Direct Variation once you have the Equation
Once you have the equation y = kx, you can find infinite additional values (points) that will work.
For example, in the first babysitting example, the equation is y = $7.50x, which we write as y = 7.5x If she babysits for 20 hours, how much did she earn?
x = 20
Once you have the equation y = kx, you can find infinite additional values (points) that will work.
For example, in the first babysitting example, the equation is y = $7.50x, which we write as y = 7.5x If she babysits for 20 hours, how much did she earn?
x = 20
so y = 7.5(20) =
150 so She earns $150.
If she earns $750, how many hours did she need to work?
If she earns $750, how many hours did she need to work?
Now y = 750 so 750
= 7.5x
It is a one-step equation and we get
x = 100 or 100 hours!
It is a one-step equation and we get
x = 100 or 100 hours!
Finding
the Equation if you know 1 point and then Finding Additional Values
y varies directly
with x. Write an equation for the direct variation. Then find each value
If y = 8 when x =
3, find y when x = 45
FIRST you need to
find k
y = kx… In this
case we have 8 = k(3) or 8 = 3k
Solve this 1 step
equation—leaving it in fraction form!
8/3= k
so
y = (8/3)x
Now, find y when x
= 45
y = (8/3)(45)
solve
y = 120
Applying
direct variation to the Distance Formula d = rt
A jet’s distance varies
directly as the hours it flies
If it traveled
3420 miles in 6 hours, how long will it take to fly 6500 miles?
k = 3420/6 =
570mph ( its speed)
6500 = 570t
t ≈11.4
about 11.4 hours
No comments:
Post a Comment