Wednesday, December 19, 2012
Math 6A ( Periods 2 & 4)
Fractions & Mixed Numbers 6-3
1/2 + 1/2 + 1/2 = 3/2
A fraction whose numerator is greater than or equal to its denominator is called an improper fraction.
Every improper fractions is greater than 1
A proper fraction is a fraction whose numerator is less than its denominator.
Thus, a proper fraction is always between 0 and 1
1/4, 2/3, 5/9. 10/12 17/18 are all proper fractions
5/2, 8/3, 18/15, 12/5 are all improper fractions
You can express any improper fraction as the sum of a whole number and a fraction
a number such as 1 1/2 is called a mixed number
If the fractional part of a mixed number is a proper fraction in lowest terms, the mixed number is said to be in simple form.
To change an improper fraction into a mixed number in simple form, divide the numerator by the denominator and express the remainder as a fraction.
14/3 = 4 2/3
30/4 = 7 2/4 = 7 1/2
To change a mixed number to an improper fraction rewrite the whole number part as a fraction with the same denominator as the fraction part and add together.
or multiply the denominator by the whole number part and add the fractional part to that...
In class I showed the circle shortcut. If you were absent, check with a friend or ask me in class!!
2 5/6 =
(2 x 6) + 5
6
=17/6
Practice these:
785 ÷ 3
852÷ 5
3751÷ 16
98001÷231
post your answers below in the comments for extra credit !!
Tuesday, December 18, 2012
Math 6 High (Period 3)
Dividing Integers 4.6
According to
your textbook, a useful way to divide integer is to think of it as a multiplication problem.
that is, when you consider -15 ÷ 3 =?
rethink it as 3 · ? = -15.
You know that (3)(-5) = -15
so you can conclude that -15 ÷ 3 = -5
Use similar reasoning for other division
problems!
More
generally, when dividing two integers, divide their absolute values and then
use the same rules applied to multiplying integers:
Specifically:
The quotient
of two positive integers is positive
The quotient
of two negative integers is positive
The quotient
of two integers with different signs is negative
The quotient
of 0 and a non-zero integer is 0.
Note: an
expression with 0 in the divisor such as
4 ÷ 0 is undefined. You cannot divide a
number by 0.
Evaluating
an expression such as -18/x
a) when x =
-3
1. First substitute in using parentheses for the
number -18/(-3)
2. Then DO THE MATH remembering that the quotient of two negative
numbers is positive.
3. The solution is +6.
b) when x =
3
1. First
substitute in using parentheses for the number
-18/(3)
2. Then DO
THE MATH remembering that the quotient of two integers with different signs is
always negative.
3. The
solution is -6.
Finding
an Average With Integers
To find the
average, always add the numbers first.
The example
in the book uses the following measurements (in feet) taken from the bottom of
Lake Michigan and find the average lake bottom’s elevation to its surface….
-844, -865, - 900,
-893, -888
so to add do
the following
-844 +
(-865) + (-900) +(-893) + (-888)
Now, I
recommend stacking them to add carefully.
Remembering the rule for adding integers—when adding integers with the
SAME sign, just add them and USE THEIR sign… so we know the total must still be
negative since they are ALL negative… and we get – 4390
Now, there are
5 numbers so we divide by +5
-4390/5
We see that
we have a negative divided by a positive.
We know our quotient will be negative
-4390/5 =
-878
So the average of the lake’s bottom elevation is
-878 feet or you could state it is 878 feet BELOW the lake surface.
Math 6 High (Period 3)
Multiplying Integers 4.5
As we
discovered any number multiplied by -1
is equal to its opposite.
-1 ∙ a = -a
We use this Multiplicative
Property of -1 to develop general rules
for multiplying integers.
Specifically:
The product of
two positive integers is positive
The product
of two negative integers is positive
The product of
two integers with different signs is negative
The product of 0 and a non-zero integer is 0.
Examples
Multiplying
Integers with the same sign:
(4)(7) = 28
(-11)(-4) =
+44
Multiplying Integers with different signs:
(5)(-5) =
-25
(-8)(9) =
-72
Evaluating
an expression such as:
a) x y
when x = -15 and y = -6
1. First substitute in using parentheses for the
numbers (-15)(-6)
2. Then DO THE MATH remembering that the product of two negative
numbers is positive.
3. The solution is +90.
b) ( -a)(b) when
a = -4 and b = -8
(Be careful with these types—they can be tricky)
1. First
substitute in using parentheses for the number
-(-4)(-8)
2. Now look
at –(-4) first that really says to take
the opposite of -4 and we know that the opposite of -4 is 4 so we really have
(4)(-8)
3. Then DO
THE MATH remembering that the product of two integers with different signs is
always negative.
4. The
solution is -32.
Multiplying
Three or MORE Integers
The
following is our textbooks instructions:
- To multiply three or more integers work from left to right, multiplying two numbers at a time.
- Find the product of the first two numbers, the multiply that product by the next number to the right
- Continue until all numbers have been multiplied to find the final product.
EXAMPLES:
(2)(-3)(4) = (-6)(4) = -24
(-4)(5)(0) =
(-20(0) = 0
My
Note: But why even do the multiplication? Any
number multiplied by 0 is 0 so you know
right away the solution is ZERO!!!
(-1)(-2)(-3)(-4)
= (2)(-3)(-4) = (-6)(-4) = 24
We discussed
in class to be a sign counter—If the number of negative signs (in your non-zero
multiplication problem) is EVEN then your solution will be POSITIVE. If the
number is ODD, then your solution will be NEGATIVE. The sign of the product depends on the number
of factors (assuming all are non-zero) that are negative.
The product
of two integers with the same sign is POSITIVE
The product of two integers with different signs
is NEGATIVE
Friday, December 14, 2012
Math 6A (Periods 2 & 4)
Equivalent Fractions 6-2
We drew the four number lines from Page 182 and noticed that 1/2, 2/4, 3/6, and 4/8 all were at the midpoints of the segment from 0 to 1. They all denoted the same number and are called equivalent fractions.
If you multiply the numerator and the denominator by the same number the results will be a fraction that is equivalent to the original fraction
1/2 = 1 x 3/2 x 3 = 3/6
It works for division as well
4/8 = 4 ÷ 4 / 4 ÷ 8 = 1/2
So we can generalize and see the following properties
For any whole numbers a, b, c, with b not equal to zero and c not equal to zero
a/b = a x c/ b x c and
a/b = a ÷ c / b ÷c
Find a fraction equivalent to 2/3 with a denominator of 12
we want a number such that 2/3 = n/12
You could look at this and say
" What do I do to 3 to get it to be 12?
Multiply by 4
so you multiply 2 by 4 and get 8 so
8/12 is an equivalent fraction
A fraction is in lowest terms if its numerator and denominator are relatively prime-- That is if their GCF is 1
3/4, 2/7, and 3/5 are in lowest terms.
They are simplified
You can write a fraction in lowest terms by dividing the numerator and denominator by their GCF.
Write 12/18 is lowest terms
The GCF (12 and 18) = 6
so 12/18 = 12÷ 6 / 18 ÷ 6 = 2/3
Find two fractions with the same denominator that are equivalent to 7/8 and 5/12
This time you need to find the least common multiple of the denominators!! or the LCD
Using the box method from Chapter 5, we find that the LCM (8, 12 ) = 24
7/8 = 7 X 3 / 8 X 3 = 21/24
and
5/12 = 5 X 2 / 12 X 2 = 10/24
When finding equations such as
3/5 = n/15 we noticed we could multiply the numerator of the first fraction by the denominator of the second fraction and set that equal to the denominator of the first fraction times the numerator of the second... or
3(15) = 5n now we have a one step equation
If we divide both sides by 5 we can isolate the variable n and solve...
3(15)/ 5 = n
9 = n
We found we could generalize
If a/b = c/d then ad = bc
Thursday, December 13, 2012
Math 6A (Periods 2 & 4)
Fractions 6-1
The symbol 1/4 can mean several things:
1) It means one divided by four
2) It represents one out of four equal parts
3) It is a number that has a position on a number line.
1/8 means 1 divided by 8 or 1 ÷ 8
A fraction consists of two numbers
The denominator tells the number of equal parts into which the whole has been divided.
The numerator tells how many of these parts are being considered.
we noted that we could abbreviate ...
denominator as
denom with a line above it
and numerator as numer
we found that you could add
1/3 + 1/3 + 1/3 = 3/3 = 1
or 1/4 + 1/4 + 1/4 + 1/4 = 4/4 = 1
we also noted that 8 X 1/8 = 8/8 = 1
We also noticed that 2/7 X 3 = 6/7
So we discussed the properties
For any whole numbers a, b,and c with b not equal to zero
1/b + 1/b + 1/b ... + 1/b = b/b = 1 for b numbers added together
and we noticed that b ∙ 1/b = b/b = 1
we also noticed that
We talked about the parking lot problem on Page 180
A count of cars and trucks was taken at a parking lot on several different days. For each count, give the fraction of the total vehicles represented by
(a) cars
(b) trucks
Given: 8 cars and 7 trucks
We noticed that you needed to find the total vehicles or 8 + 7 = 15 vehicles
(a) fraction represented by cars is 8/15
(b) fraction represented by trucks is 7/15
What if the given was: 12 trucks and 15 cars
(a) fraction represented by cars is 15/27
(b) fraction represented by trucks is 12/27
What about
GIVEN:
9 cars and 35 vehicles
This time we need to find out how many trucks there are
35 - 9 = 26
so
(a) 9/35
(b) 26/35
We aren't simplifying YET
Wednesday, December 12, 2012
Math 6High (Period 3)
Subtracting Integers 4.4
So to generalize the rules we discussed in class, when using
a number line to show subtraction (Looking at Page 181 at the number line examples):
To subtract a positive integer , move in the negative
direction
To subtract a negative integer, move in the positive
direction.
ADD The Opposite!
We had a huge discussion about way too pessimistic people and how we wish we could take away a little of their negativity… and about too positive people—even someone in our class [ :) ] whom some of us wished was just a little less positive!! We talked about how instead of taking away a little – if we gave a little of the opposite—that might work as well… and we realized that this applies to math as well.
We had a huge discussion about way too pessimistic people and how we wish we could take away a little of their negativity… and about too positive people—even someone in our class [ :) ] whom some of us wished was just a little less positive!! We talked about how instead of taking away a little – if we gave a little of the opposite—that might work as well… and we realized that this applies to math as well.
ADD THE OPPOSITE
That is, instead of subtracting a number—add it’s opposite.
Then use the rules for adding integers that you have learned from the previous
lessons
In general: a - b = a + (-b)
Several examples:
6 – 8 = 6 + (-8) In
this case by adding the opposite, you are adding two integers with different signs—so you following the
adding integers with DIFFERENT SIGNS RULE. Ask “Who wins?” and “by how much?” The negative wins by 2 so the answer is
-2
6-8 = -2
-9 - 10 = -9 + (-10)
In this case you are adding two integers with the same sign. So use the SAME
SIGN RULE. -9 + (-10) = -19
What about
54- (-12) = 54 + (+12) = 54 + 12 In this case you are adding two integers with
the same sign. So use the SAME SIGN RULE.
54 –(-12) = 66
We talked about
making sure to double check—that is, check, check—both places- where you change the subtraction sign
to a positive AND where you change the second numbers sign to its opposite.
Friday, December 7, 2012
Math 6High(Period 3)
Adding Integers
Using Addition Rules 4.3
Absolute Value of a number--> is its distance from ZERO on a number line.
The absolute value of a number a is
written as
The absolute value of any number is always positive because
absolute value is a distance concept—and distances are always POSITIVE
When Adding Integers using the following rules:
To add two integers with the same sign, just add them and
use their sign.
To add two integers with different signs, subtract the lesser
absolute value from the greater absolute value and write the sign of the integer
with the greater absolute value.
We called this “Who Wins?... and “ By How Much?”
We called this “Who Wins?... and “ By How Much?”
That is you decide who is the winner (the
integer with the greater absolute value) and you take the difference ( subtract
the smaller absolute value from the larger absolute value). Use the “winner’s
sign.”
Identity Property of Addition:
The sum of zero and any
integer is the integer
0 + (-3) = -3
Zero is called the ADDITIVE IDENTITY.
The sum of -3 and -5 is negative because
-3 + -5 are both
negative --> they
have the same sign
-3+ -5 = -8
But what about
-5 + 3= ?
These are two integers with DIFFERENT SIGNS… Who wins? The
negative… by how much? 5-3 = 2 so the
solutions is – 5 + 3 = -2
What about 5 + (-3) ?
Again these are two integers with DIFFERENT SIGNS… Who wins?
This time the positive… by how much? 5-3 = 2 so the solutions is 5 +(-3) = 2
Here are a number of good strategies to use when adding more
than just two integers….
When adding a series of numbers use the commutative and
associative properties of addition to group numbers with the same sign.
- First, always look for ZERO PAIRS (they cancel each other out)—giving you less work to do!
- Find the sum of the positive numbers and the sum of the negative numbers. Then add the two sums.
Finding the average of integers is just the same as finding
the average of natural numbers. Just remember to use the strategies above to
combine positive and negative numbers.
For instance The daily temperature for one week in Helene Montana in the winter was 5ºC , 3ºC, 2ºC, 0ºC, -2ºC, -3ºC -4ºC .
For instance The daily temperature for one week in Helene Montana in the winter was 5ºC , 3ºC, 2ºC, 0ºC, -2ºC, -3ºC -4ºC .
Notice,
there are 7 degrees listed for the 7 days—even though one of them was 0ºC.
You need to make sure you use the 7 temperatures.
You need to make sure you use the 7 temperatures.
In this
case I would use zero pairs to add 3 + (-3) and 2 + (-2) and I am left with only adding 5 +
(-4) = 1 that was easy.... where is my Easy Button?
Now divide 1 by the number of temperatures we started with-- that was 7 for the 7 days...
1 /7 is
0.142857…. which would round to a very chilly 0.14ºC
Wednesday, December 5, 2012
Algebra Honors (Periods 5 & 6)
Adding & Subtracting Fractions 6-5
In chapter 2 Section 9 we reviewed adding and subtracting
fractions.
With that we found we could do the reverse….
To add or subtract fractions with the same denominator, you
add or subtract their numerators and write that results over the common
denominator.
To simplify an expression involving fractions, you write it as
a single fraction in simplest form
3c/16 + 5c/16 = 8c/16 = c/2
Be careful when you distribute the subtraction sign to every
term in the 2nd fraction.
The following really seems simple but many students try to
simplify it… BE CAREFUL
STOP! You can not
simplify any farther!
Notice that 3-x = -( x - 3) , the LCD is x – 3
Simplify
You must determine the LCD first. Rewrite the fractions using
the LCD of 36
Simplify:
Simplify:
Factor completely FIRST
You realize that the LCD is a(a-2)(a+2)
Math 6High ( Period 3)
Adding Integers on a Number Line 4.2
We used the number line to model adding two positive
numbers—and we developed a similar pattern for adding integers.
Please look at our textbook page 171 to see
the examples of adding integers—the book uses the color blue to indicate a
positive number’s movement along the number line and the color red to indicate
movement to the left representing a negative number.
You will discover that
2 + (-5) = -3
-6 + 8 = 2
Two numbers are opposite if they are the SAME distance from
0 on the number line but are opposite sides of ZERO.
For example -3 and 3 are opposites because they
are both 3 units away from zero.
Again -3 can be read as “the opposite of 3” as well as
“negative 3”.
The expressions –(-3) can be read as “the opposite of negative
three” which would be +3
Inverse Property of Addition
Words:
Words:
The sum of a number and its opposite is zero
Algebraic:
a + (-a) = 0
Tuesday, December 4, 2012
Algebra Honors (Periods 5 & 6)
Adding & Subtracting Fractions
The Least Common Denominator 6-4
The Least Common Denominator 6-4
We know that we can write a fraction in simpler form by dividing
its numerator and denominator by the same nonzero number.
and the reverse is true as well
You can write a fraction in a different form by multiplying
the numerator and denominator by the same nonzero number.
3/7 = ?/35
You realize that you multiply 7 by 5 to obtain 35 so you would
multiply 3 by 5 to obtain the correct number for the numerator.
3/7 = 15/35
the same applies to fractions with variables…
8/3a = ?/18a2
What do you multiply 3a by to obtain 18a2? 6a
so you must multiply both by 6a
Complete:
You notice that you need to multiply the denominator by (x +1)
so you must do the same to the numerator.
When you add or subtract fractions with different
denominators, you will find that using the Least Common Denominator (LCD) will simplify your work
Find the LCD of:
First factor each denominator completely. Factor Integers into
primes!
6x - 30 = 6(x - 5)= 2·3(x - 5)
9x - 45 = 9(x - 5) = 3∙3(x - 5)
Form the product of the greatest power of each
(Remember that the LCM is the product of every factor to its greatest power)
(Remember that the LCM is the product of every factor to its greatest power)
2·32(x - 5) = 18(x - 5)
Therefore the LCD is 18( x – 5)
Re write the following with their LCD
x2 - 8x +16 = (x - 4)2
and
x2- 7x + 12 = (x - 4)(x - 3)
the LCD is (x -4)2(x -3)
Now rewrite each fraction using the LCD
and
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