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Friday, September 23, 2011

Algebra Honors (Period 6 & 7)

Powers of Monomials 4-4


POWER TO ANOTHER POWER


MULTIPLY the POWERS
(m5)3 = m15


To check, EXPAND it out:
(m5)(m5)(m5) = m15



PRODUCT TO A POWER

DISTRIBUTE the power to EACH FACTOR
(m5n4)3 = m15n12



(am)n = a mn
(u4)5 = u20
(2x)3 = (2x)(2x)(2x) = 8x3

(ab)m = (ab)(ab)(ab).... -->m factors<--- = (a⋅a⋅a⋅a⋅a ...)(b⋅b⋅b⋅b⋅b ...) where a is multiplied m number of times and b is multiplied m number of times.... (ab)m = ambm
To find the power of a product, you find the power of each factor and then multiply

Simplify
(-2k)5
= (-2)5 k5 = -32k5

Evaluate if t = 2
a) 3t3
b) (3t)3
c) 33t3
d) -(3t)3


Simplify
(-3x2y5)3
(-3)3(x2)3(y5)3
-27x6y15



RAISING A QUOTIENT TO A POWER:


DISTRIBUTE THE POWER to the numerator and the denominator

(m2/n6)3 = m6/n18

1/n6 = n-6
so what does
1/m-7 =?

Let's read it in math terms
it is 1 divided by 1/m7 .. and what do you do when you need to divide by a fraction? You multiply by its reciprocal so

1 divided by 1/m7 = 1 ÷ 1/m7 = 1× m7/1 = m7

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