Fractions & Mixed Numbers 6-3
1/2 + 1/2 + 1/2 = 3/2
A fraction whose numerator is greater than or equal to its denominator is called an improper fraction.
Every improper fractions is greater than 1
A proper fraction is a fraction whose numerator is less than its denominator.
Thus, a proper fraction is always between 0 and 1
1/4, 2/3, 5/9. 10/12 17/18 are all proper fractions
5/2, 8/3, 18/15, 12/5 are all improper fractions
You can express any improper fraction as the sum of a whole number and a fraction
a number such as 1 1/2 is called a mixed number
If the fractional part of a mixed number is a proper fraction in lowest terms, the mixed number is said to be in simple form.
To change an improper fraction into a mixed number in simple form, divide the numerator by the denominator and express the remainder as a fraction.
14/3 = 4 2/3
30/4 = 7 2/4 = 7 1/2
To change a mixed number to an improper fraction rewrite the whole number part as a fraction with the same denominator as the fraction part and add together.
or multiply the denominator by the whole number part and add the fractional part to that...
In class I showed the circle shortcut. If you were absent, check with a friend or ask me in class!!
2 5/6 =
(2 x 6) + 5
6
=17/6
Practice these:
785 ÷ 3
852÷ 5
3751÷ 16
98001÷231
post your answers below in the comments for extra credit !!
Friday, January 6, 2012
Thursday, January 5, 2012
Wednesday, January 4, 2012
Math 6 Honors ( Periods 1, 2, & 3)
Equivalent Fractions 6-2
We drew the four number lines from Page 182 and noticed that 1/2, 2/4, 3/6, and 4/8 all were at the midpoints of the segment from 0 to 1. They all denoted the same number and are called equivalent fractions.
If you multiply the numerator and the denominator by the same number the results will be a fraction that is equivalent to the original fraction
1/2 = 1 x 3/2 x 3 = 3/6
It works for division as well
4/8 = 4 ÷ 4 / 4 ÷ 8 = 1/2
So we can generalize and see the following properties
For any whole numbers a, b, c, with b not equal to zero and c not equal to zero
a/b = a x c/ b x c and
a/b = a ÷ c / b ÷c
Find a fraction equivalent to 2/3 with a denominator of 12
we want a number such that 2/3 = n/12
You could look at this and say
" What do I do to 3 to get it to be 12?
Multiply by 4
so you multiply 2 by 4 and get 8 so
8/12 is an equivalent fraction
A fraction is in lowest terms if its numerator and denominator are relatively prime-- That is if their GCF is 1
3/4, 2/7, and 3/5 are in lowest terms.
They are simplified
You can write a fraction in lowest terms by dividing the numerator and denominator by their GCF.
Write 12/18 is lowest terms
The GCF (12 and 18) = 6
so 12/18 = 12÷ 6 / 18 ÷ 6 = 2/3
Find two fractions with the same denominator that are equivalent to 7/8 and 5/12
This time you need to find the least common multiple of the denominators!! or the LCD
Using the box method from Chapter 5, we find that the LCM (8, 12 ) = 24
7/8 = 7 X 3 / 8 X 3 = 21/24
and
5/12 = 5 X 2 / 12 X 2 = 10/24
When finding equations such as
3/5 = n/15 we noticed we could multiply the numerator of the first fraction by the denominator of the second fraction and set that equal to the denominator of the first fraction times the numerator of the second... or
3(15) = 5n now we have a one step equation
If we divide both sides by 5 we can isolate the variable n and solve...
3(15)/ 5 = n
9 = n
We found we could generalize
If a/b = c/d then ad = bc
We drew the four number lines from Page 182 and noticed that 1/2, 2/4, 3/6, and 4/8 all were at the midpoints of the segment from 0 to 1. They all denoted the same number and are called equivalent fractions.
If you multiply the numerator and the denominator by the same number the results will be a fraction that is equivalent to the original fraction
1/2 = 1 x 3/2 x 3 = 3/6
It works for division as well
4/8 = 4 ÷ 4 / 4 ÷ 8 = 1/2
So we can generalize and see the following properties
For any whole numbers a, b, c, with b not equal to zero and c not equal to zero
a/b = a x c/ b x c and
a/b = a ÷ c / b ÷c
Find a fraction equivalent to 2/3 with a denominator of 12
we want a number such that 2/3 = n/12
You could look at this and say
" What do I do to 3 to get it to be 12?
Multiply by 4
so you multiply 2 by 4 and get 8 so
8/12 is an equivalent fraction
A fraction is in lowest terms if its numerator and denominator are relatively prime-- That is if their GCF is 1
3/4, 2/7, and 3/5 are in lowest terms.
They are simplified
You can write a fraction in lowest terms by dividing the numerator and denominator by their GCF.
Write 12/18 is lowest terms
The GCF (12 and 18) = 6
so 12/18 = 12÷ 6 / 18 ÷ 6 = 2/3
Find two fractions with the same denominator that are equivalent to 7/8 and 5/12
This time you need to find the least common multiple of the denominators!! or the LCD
Using the box method from Chapter 5, we find that the LCM (8, 12 ) = 24
7/8 = 7 X 3 / 8 X 3 = 21/24
and
5/12 = 5 X 2 / 12 X 2 = 10/24
When finding equations such as
3/5 = n/15 we noticed we could multiply the numerator of the first fraction by the denominator of the second fraction and set that equal to the denominator of the first fraction times the numerator of the second... or
3(15) = 5n now we have a one step equation
If we divide both sides by 5 we can isolate the variable n and solve...
3(15)/ 5 = n
9 = n
We found we could generalize
If a/b = c/d then ad = bc
Algebra Honors (Period 6 & 7)
Rational Square Roots 11-3
You know that subtraction undoes addition, and that division by a nonzero number undoes multiplication, Similarly squaring a number can be undone by finding a square root.
If a2 = b then a is a square root of b
Notice that 72= 49 and so does (-7)2 = 49
So 7 and -7 are square roots of 49
the radical symbol √ is used to write the principal or positive square root of a positive number.
is read “The positive square root of 49 equals 7
A negative square root is associated with the symbol - √
is read “The negative square root of 49 equals -7”
Let’s use ± to indicate both the positive and negative square root
so ±√49 means the positive or negative square root of 49 or ±7
Let’s look at √49 the number written beneath the radical sign (such as 49) is called the radicand.
For all positive real numbers a:
Every positive real number a has two square roots
The symbol √a denotes the principal square root of a
Zero has only one square root—itself.
Because the square of every real number is either positive or zero—NEGATIVE NUMBERS DO NOT HAVE SQUARE ROOTS IN THE SET OF REAL NUMBERS.
does not have a solution in the set of real numbers!!
Notice that SQRT(4•25)=SQRT(100) = 10 and
that SQRT (4) • SQRT(25) = 2 • 5 = 10
so
Product Property of Square Roots
For any nonnegative real numbers a and b,
SQRT(AB) = SQRT(A) •SQRT(B)
Find:
Let’s say you forgot your perfect squares—OH MY!!
but looking at 225, using your skills from previous years you realize 225= 9 • 25 so
SQRT 225= SQ•5 =15RT(9 •25) = 3•5 =15
What about SQRT 2304
If you cannot see any perfect squares that divide the radicand—begin by factoring it!!
Then see if you have any perfect squares. USE INVERTED DIVISION!!
use inverted division along with divisibility rules to find perfect squares
Look for the largest perfect square factors and you discover that
SQRT (2304) = SQRT(22•32•82) = 2•3•8= 48
You know that subtraction undoes addition, and that division by a nonzero number undoes multiplication, Similarly squaring a number can be undone by finding a square root.
If a2 = b then a is a square root of b
Notice that 72= 49 and so does (-7)2 = 49
So 7 and -7 are square roots of 49
the radical symbol √ is used to write the principal or positive square root of a positive number.
is read “The positive square root of 49 equals 7
A negative square root is associated with the symbol - √
is read “The negative square root of 49 equals -7”
Let’s use ± to indicate both the positive and negative square root
so ±√49 means the positive or negative square root of 49 or ±7
Let’s look at √49 the number written beneath the radical sign (such as 49) is called the radicand.
For all positive real numbers a:
Every positive real number a has two square roots
The symbol √a denotes the principal square root of a
Zero has only one square root—itself.
Because the square of every real number is either positive or zero—NEGATIVE NUMBERS DO NOT HAVE SQUARE ROOTS IN THE SET OF REAL NUMBERS.
does not have a solution in the set of real numbers!!
Notice that SQRT(4•25)=SQRT(100) = 10 and
that SQRT (4) • SQRT(25) = 2 • 5 = 10
so
Product Property of Square Roots
For any nonnegative real numbers a and b,
SQRT(AB) = SQRT(A) •SQRT(B)
Find:
Let’s say you forgot your perfect squares—OH MY!!
but looking at 225, using your skills from previous years you realize 225= 9 • 25 so
SQRT 225= SQ•5 =15RT(9 •25) = 3•5 =15
What about SQRT 2304
If you cannot see any perfect squares that divide the radicand—begin by factoring it!!
Then see if you have any perfect squares. USE INVERTED DIVISION!!
use inverted division along with divisibility rules to find perfect squares
Look for the largest perfect square factors and you discover that
SQRT (2304) = SQRT(22•32•82) = 2•3•8= 48
Tuesday, January 3, 2012
Algebra Honors (Period 6 & 7)
Decimal Forms of Rational Numbers 11-2
Any common fraction can be written as a decimal by dividing the numerator by the denominator. If the remainder is zero, the decimal is called a terminating, or ending, or finite decimal.
3/8
Actually this is one of the fractions you need to know by heart !
If you don’t a remainder of zero when dividing the numerator by the denominator, continue to divide until the remainder begins to repeat.
5/6
7/11
3 2/7
The decimal quotient above are nonterminating, nonending, or infinite. The dots indicate that the decimals continue without end.
They are also called repeating or periodic because the same digit or block of digits repeats unendingly. A bar (vinculum) is used to indicate the block of digits that repeat.
What ones do you need to know by heat… same from 6th grade
1/3 family, 1/11 family, and let’s look at the 1/7 family (my favorite)
Let’s look at this algebraically… when you divide a positive integer n by a positive integer d, the remainder r at each step must be zero or a positive integer less than d. For example, if the divisor is 6, the reminders will be 0, 1, 2, 3, 4, or 5 and the division will terminate or begin repeating within 5 steps after only zeros remain to be brought down.
For every integer n and every positive integer d, the decimal form of the rational number n/d either terminates or eventually repeats in a block of fewer than d digits.
Any common fraction can be written as a decimal by dividing the numerator by the denominator. If the remainder is zero, the decimal is called a terminating, or ending, or finite decimal.
3/8
Actually this is one of the fractions you need to know by heart !
If you don’t a remainder of zero when dividing the numerator by the denominator, continue to divide until the remainder begins to repeat.
5/6
7/11
3 2/7
The decimal quotient above are nonterminating, nonending, or infinite. The dots indicate that the decimals continue without end.
They are also called repeating or periodic because the same digit or block of digits repeats unendingly. A bar (vinculum) is used to indicate the block of digits that repeat.
What ones do you need to know by heat… same from 6th grade
1/3 family, 1/11 family, and let’s look at the 1/7 family (my favorite)
Let’s look at this algebraically… when you divide a positive integer n by a positive integer d, the remainder r at each step must be zero or a positive integer less than d. For example, if the divisor is 6, the reminders will be 0, 1, 2, 3, 4, or 5 and the division will terminate or begin repeating within 5 steps after only zeros remain to be brought down.
For every integer n and every positive integer d, the decimal form of the rational number n/d either terminates or eventually repeats in a block of fewer than d digits.
Thursday, December 15, 2011
Algebra Honors (Period 6 & 7)
Properties of Rational Numbers 11-1
A real number that can be expressed as the quotient of two integers is called a rational number
A rational number can be written as a quotient of integers in an unlimited number of ways.
3 = 3/1= 6/2 = 12/4 = -15/-5
To determine which of two rational numbers is greater, you can write them with the same positive denominator and compare the numerators
Which is greater 8/3 or 17/7?
the LCD is 21
8/3 = 56/21
17/7 = 51/21
so 8/3 > 17/7
For all integers a and b and all positive integers c and d
a/c > b/d if an only if ad > bc
a/c < b/d if and only if ad < bc This method compares the product of the extremes with the product of the means Thus 4/7 > 3/8 because (4)(8) > (3)(7)
The Density Property for Rational Numbers
Between every pair of different rational numbers there is another rational number
The density property implies that it is possible to find an unlimited or endless umber of rational numbers between two given rational numbers.
If a and b are rational numbers and a< b then the number halfway from a to b is
a + (1/2)(b-a);
the number one third of the way from a to b would be
a + (1/3)(b-a) and so on
A real number that can be expressed as the quotient of two integers is called a rational number
A rational number can be written as a quotient of integers in an unlimited number of ways.
3 = 3/1= 6/2 = 12/4 = -15/-5
To determine which of two rational numbers is greater, you can write them with the same positive denominator and compare the numerators
Which is greater 8/3 or 17/7?
the LCD is 21
8/3 = 56/21
17/7 = 51/21
so 8/3 > 17/7
For all integers a and b and all positive integers c and d
a/c > b/d if an only if ad > bc
a/c < b/d if and only if ad < bc This method compares the product of the extremes with the product of the means Thus 4/7 > 3/8 because (4)(8) > (3)(7)
The Density Property for Rational Numbers
Between every pair of different rational numbers there is another rational number
The density property implies that it is possible to find an unlimited or endless umber of rational numbers between two given rational numbers.
If a and b are rational numbers and a< b then the number halfway from a to b is
a + (1/2)(b-a);
the number one third of the way from a to b would be
a + (1/3)(b-a) and so on
Math 6 Honors ( Periods 1, 2, & 3)
Fractions 6-1
The symbol 1/4 can mean several things:
1) It means one divided by four
2) It represents one out of four equal parts
3) It is a number that has a position on a number line.
1/8 means 1 divided by 8 or 1 ÷ 8
A fraction consists of two numbers
The denominator tells the number of equal parts into which the whole has been divided.
The numerator tells how many of these parts are being considered.
we noted that we could abbreviate ...
denominator as denom with a line above it
and numerator as numer
we found that you could add
1/3 + 1/3 + 1/3 = 3/3 = 1
or 1/4 + 1/4 + 1/4 + 1/4 = 4/4 = 1
we also noted that 8 X 1/8 = 8/8 = 1
We also noticed that 2/7 X 3 = 6/7
So we discussed the properties
For any whole numbers a, b,and c with b not equal to zero
1/b + 1/b + 1/b ... + 1/b = b/b = 1 for b numbers added together
and we noticed that b X 1/b = b/b = 1
we also noticed that
(a/b) X c = ac/b
We talked about the parking lot problem on Page 180
A count of cars and trucks was taken at a parking lot on several different days. For each count, give the fraction of the total vehicles represented by
(a) cars
(b) trucks
Given: 8 cars and 7 trucks
We noticed that you needed to find the total vehicles or 8 + 7 = 15 vehicles
so
(a) fraction represented by cars is 8/15
(b) fraction represented by trucks is 7/15
What if the given was: 12 trucks and 15 cars
(a) fraction represented by cars is 15/27
(b) fraction represented by trucks is 12/27
What about
GIVEN:
9cars
35 vehicles
This time we need to find out how many trucks there are
35 -9 = 26
so
(a) 9/35
(b) 26/35
We aren't simplifying YET
The symbol 1/4 can mean several things:
1) It means one divided by four
2) It represents one out of four equal parts
3) It is a number that has a position on a number line.
1/8 means 1 divided by 8 or 1 ÷ 8
A fraction consists of two numbers
The denominator tells the number of equal parts into which the whole has been divided.
The numerator tells how many of these parts are being considered.
we noted that we could abbreviate ...
denominator as denom with a line above it
and numerator as numer
we found that you could add
1/3 + 1/3 + 1/3 = 3/3 = 1
or 1/4 + 1/4 + 1/4 + 1/4 = 4/4 = 1
we also noted that 8 X 1/8 = 8/8 = 1
We also noticed that 2/7 X 3 = 6/7
So we discussed the properties
For any whole numbers a, b,and c with b not equal to zero
1/b + 1/b + 1/b ... + 1/b = b/b = 1 for b numbers added together
and we noticed that b X 1/b = b/b = 1
we also noticed that
(a/b) X c = ac/b
We talked about the parking lot problem on Page 180
A count of cars and trucks was taken at a parking lot on several different days. For each count, give the fraction of the total vehicles represented by
(a) cars
(b) trucks
Given: 8 cars and 7 trucks
We noticed that you needed to find the total vehicles or 8 + 7 = 15 vehicles
so
(a) fraction represented by cars is 8/15
(b) fraction represented by trucks is 7/15
What if the given was: 12 trucks and 15 cars
(a) fraction represented by cars is 15/27
(b) fraction represented by trucks is 12/27
What about
GIVEN:
9cars
35 vehicles
This time we need to find out how many trucks there are
35 -9 = 26
so
(a) 9/35
(b) 26/35
We aren't simplifying YET
Monday, December 5, 2011
Math 6 Honors ( Periods 1, 2, & 3)
Least Common Multiple 5-6
Here is a review of that lesson...
Let’s look at the nonzero multiples of 8 and 12—listed in order
Multiples of 8: 8, 16, 24, 32, 40, 48, 56, 64, 72…
Multiples of 12: 12, 24, 36, 48, 60, 72, ….
The numbers 24, 48, and 72, ... are called common multiples of 8 and 12. The least of these multiples is 24 and is therefore called the least common multiple.
LCM(8, 12) = 24
To find the LCM of two whole numbers, we can write out lists of multiples of the two numbers.
Or, we can use prime factorization
Lets find LCM(12, 15)
12 = 22∙3
15 = 3∙5
The LCM will be made up of the greatest power of each factor
LCM will be 22∙3∙5 = 60
The book has a third option or method
you can check out, if you’d like
Let’s find LCM (54, 60)
54= 2∙3∙3∙3 = 2∙33
60 = 2∙2∙3∙5 = 22∙3∙5
The greatest power of 2 that occurs in either prime factorization is 22
The greatest power of 3 that occurs in either prime factorization is 33
The greatest power of 5 that occurs in either prime factorization is 5
Therefore, LCM(54,60) is 22∙33∙5 = 540
REMEMBER:
The GCF (greatest common factor) is a factor. The GCF of two numbers will be either the smaller of the two or smaller than both
The LCM (least common multiple) is a multiple. The LCM of the two numbers will be the largest of the two or larger than both.
To find the LCM of two whole numbers you could write out the lists of multiples-- and that works relatively easily with small numbers... but there are more efficient ways to find the least common multiple of two whole numbers.
1. Write out the first few multiples of the larger of the two numbers and test each multiple for divisibility by the smaller number. The first multiple of the larger number that is divisible by the smaller number is the LCM
2. You can use prime factorization to find the LCM. The LCM is EVERY factor to its GREATEST power!!
LCM(54, 60)
54 = 2⋅ 3⋅ 3⋅ 3 = 2⋅ 33
60 = 2⋅ 2⋅ 3⋅ 5 = 22⋅ 3⋅ 5
So the greatest power of 2 is 22
The greatest power of 3 is just 3
and the greatest pwoer of 5 is just 5
so the product of 22⋅ 3⋅ 5 will be the LCM
LCM(54, 60) = 540
3. You may use the BOX method as shown in class... unfortunately it does not show well here. Remember you need to create a L. The numbers on the side of the box represent the GCF!! You need to multiple them with the last row of factors.
See me before or after class if you want any review!!
We reviewed the concept of relatively prime and noticed that any two prime numbers are relatively prime. We also noticed that if two numbers are relatively prime-- neither of them must be prime....
We also found out that if one number is a factor of a second number, the GCF of the two numbers is the first number AND... if one whole number is a factor of a second whole number the LCM of the two numbers is the second number!!
GCF(12,24) = 12
LCM(12,24) = 24
WOW!!
If two whole numbers are relatively prime---
their GCF = 1
and their LCM is their product!!
GCF(8,9) =1
GCF(8,9) = 72
WOW!!
LCM & GCF Story PRoblems
1) Read the problem
2) Re-read the problem!!
3) Figure out what is being asked for!!
4) find the "magic " word... to help you determine if you are finding GCF or LCM
5) When in doubt... draw it out!!
Here is a review of that lesson...
Let’s look at the nonzero multiples of 8 and 12—listed in order
Multiples of 8: 8, 16, 24, 32, 40, 48, 56, 64, 72…
Multiples of 12: 12, 24, 36, 48, 60, 72, ….
The numbers 24, 48, and 72, ... are called common multiples of 8 and 12. The least of these multiples is 24 and is therefore called the least common multiple.
LCM(8, 12) = 24
To find the LCM of two whole numbers, we can write out lists of multiples of the two numbers.
Or, we can use prime factorization
Lets find LCM(12, 15)
12 = 22∙3
15 = 3∙5
The LCM will be made up of the greatest power of each factor
LCM will be 22∙3∙5 = 60
The book has a third option or method
you can check out, if you’d like
Let’s find LCM (54, 60)
54= 2∙3∙3∙3 = 2∙33
60 = 2∙2∙3∙5 = 22∙3∙5
The greatest power of 2 that occurs in either prime factorization is 22
The greatest power of 3 that occurs in either prime factorization is 33
The greatest power of 5 that occurs in either prime factorization is 5
Therefore, LCM(54,60) is 22∙33∙5 = 540
REMEMBER:
The GCF (greatest common factor) is a factor. The GCF of two numbers will be either the smaller of the two or smaller than both
The LCM (least common multiple) is a multiple. The LCM of the two numbers will be the largest of the two or larger than both.
To find the LCM of two whole numbers you could write out the lists of multiples-- and that works relatively easily with small numbers... but there are more efficient ways to find the least common multiple of two whole numbers.
1. Write out the first few multiples of the larger of the two numbers and test each multiple for divisibility by the smaller number. The first multiple of the larger number that is divisible by the smaller number is the LCM
2. You can use prime factorization to find the LCM. The LCM is EVERY factor to its GREATEST power!!
LCM(54, 60)
54 = 2⋅ 3⋅ 3⋅ 3 = 2⋅ 33
60 = 2⋅ 2⋅ 3⋅ 5 = 22⋅ 3⋅ 5
So the greatest power of 2 is 22
The greatest power of 3 is just 3
and the greatest pwoer of 5 is just 5
so the product of 22⋅ 3⋅ 5 will be the LCM
LCM(54, 60) = 540
3. You may use the BOX method as shown in class... unfortunately it does not show well here. Remember you need to create a L. The numbers on the side of the box represent the GCF!! You need to multiple them with the last row of factors.
See me before or after class if you want any review!!
We reviewed the concept of relatively prime and noticed that any two prime numbers are relatively prime. We also noticed that if two numbers are relatively prime-- neither of them must be prime....
We also found out that if one number is a factor of a second number, the GCF of the two numbers is the first number AND... if one whole number is a factor of a second whole number the LCM of the two numbers is the second number!!
GCF(12,24) = 12
LCM(12,24) = 24
WOW!!
If two whole numbers are relatively prime---
their GCF = 1
and their LCM is their product!!
GCF(8,9) =1
GCF(8,9) = 72
WOW!!
LCM & GCF Story PRoblems
1) Read the problem
2) Re-read the problem!!
3) Figure out what is being asked for!!
4) find the "magic " word... to help you determine if you are finding GCF or LCM
5) When in doubt... draw it out!!
Friday, December 2, 2011
Math 6 Honors ( Periods 1, 2, & 3)
Greatest Common Factor 5-5
If we list the factors of 30 and 42, we notice
Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30
Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42
We notice that 1, 2, 3, and 6 are all COMMON factors of these two numbers. The number 6 is the greatest of these and therefore is called the
GREATEST COMMON FACTOR of the two numbers. We write
GCF(30,42) = 6
Although listing the factors of two numbers and then comparing their common factors is one way to determine the greatest common factor, using prime factorization is another easy way to find the GCF
Find GCF(54, 72)
54 = 2 ⋅ 3 ⋅ 3 ⋅ 3
72 = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 3
Find the greatest power of 2 that occurs IN BOTH prime factorization. The greatest power of 2 that occurs in both is just 2 1
Find the greatest power of 3 that occurs IN BOTH prime factorizations. The greatest power of 3 that occurs in both is 32
Therefore
GCF(54, 72) = 2 ⋅ 32 = 18
In class we circled the common factors and realized that
GCF(54, 72) = 2 ⋅ 3 ⋅ 3 = 18
Fin the GCF( 45, 60)
45 = 3 ⋅ 3⋅ 5
60 = 2⋅ 2⋅ 3⋅ 5
Since 2 is NOT a factor of 45-- there is NO greatest power of 2 that occurs in both prime factorizations.
The greatest power of 3 is just 31
and the greatest power of 5 is just 51
Therefore,
GCF(45,60) = 3⋅ 5 = 15
The number 1 is a common factor of any two whole numbers!! If 1 is the GCF , then the two numbers are said to be RELATIVELY PRIME. Two numbers can be relatively prime even if one or both of them are composite.
Show that 15 and 16 are relatively prime
List the factors of each number
FACTORS of 15: 1, 3, 5, 15
FACTORS of 16: 1, 2, 4, 8, 16
Since the GCF(15,16) = 1. The two numbers are relatively prime!!
If we list the factors of 30 and 42, we notice
Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30
Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42
We notice that 1, 2, 3, and 6 are all COMMON factors of these two numbers. The number 6 is the greatest of these and therefore is called the
GREATEST COMMON FACTOR of the two numbers. We write
GCF(30,42) = 6
Although listing the factors of two numbers and then comparing their common factors is one way to determine the greatest common factor, using prime factorization is another easy way to find the GCF
Find GCF(54, 72)
54 = 2 ⋅ 3 ⋅ 3 ⋅ 3
72 = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 3
Find the greatest power of 2 that occurs IN BOTH prime factorization. The greatest power of 2 that occurs in both is just 2 1
Find the greatest power of 3 that occurs IN BOTH prime factorizations. The greatest power of 3 that occurs in both is 32
Therefore
GCF(54, 72) = 2 ⋅ 32 = 18
In class we circled the common factors and realized that
GCF(54, 72) = 2 ⋅ 3 ⋅ 3 = 18
Fin the GCF( 45, 60)
45 = 3 ⋅ 3⋅ 5
60 = 2⋅ 2⋅ 3⋅ 5
Since 2 is NOT a factor of 45-- there is NO greatest power of 2 that occurs in both prime factorizations.
The greatest power of 3 is just 31
and the greatest power of 5 is just 51
Therefore,
GCF(45,60) = 3⋅ 5 = 15
The number 1 is a common factor of any two whole numbers!! If 1 is the GCF , then the two numbers are said to be RELATIVELY PRIME. Two numbers can be relatively prime even if one or both of them are composite.
Show that 15 and 16 are relatively prime
List the factors of each number
FACTORS of 15: 1, 3, 5, 15
FACTORS of 16: 1, 2, 4, 8, 16
Since the GCF(15,16) = 1. The two numbers are relatively prime!!
Wednesday, November 30, 2011
Algebra Honors (Period 6 & 7)
Multiplying Fractions 6-2
You know from previous years that
ac/bd = a/b ⋅ c/d
and you know the converse is also true
a/b ⋅ c/d = ac/bd
That means you could solve
8/9⋅3/10 by either multiplying first and then simplify or you could simplify first and then multiply.
I find it works so much better to simplify first
8/9⋅3/10 = 4/15
6x/y3⋅y2/15 = 2x/5y where y ≠0
Which simplifies to
This textbook wants us to keep the factored form as our answers--> so let's continue to do that. In addition it states, " ...from now on, assume that the domains of the variables do not include values for which any denominator is ZERO. Therefore it will NOT be necessary to show the excluded [or restrictions] values of the variables."
I know everyone is jumping for joy!!
Rule of Exponents for a Power of a Quotient
(a/b)m = am/bm
(x/3)3 = x3/27
(-c/2)2⋅4/3c
you must do the exponent portion first!!
c2/4⋅(4/3c)
c/3
Find the volume of a cube if each edge has length 6n/7 in
You just need to cube each factor
(6n/7)3 = 216n3/343 inches cubed
If you traveled for 7t/60 hours at 80r/9 mi/h, how far have you gone?
Just multiply
7t/60⋅80r/9
but simplify first and you get
28rt/27 miles
You know from previous years that
ac/bd = a/b ⋅ c/d
and you know the converse is also true
a/b ⋅ c/d = ac/bd
That means you could solve
8/9⋅3/10 by either multiplying first and then simplify or you could simplify first and then multiply.
I find it works so much better to simplify first
8/9⋅3/10 = 4/15
6x/y3⋅y2/15 = 2x/5y where y ≠0
Which simplifies to
This textbook wants us to keep the factored form as our answers--> so let's continue to do that. In addition it states, " ...from now on, assume that the domains of the variables do not include values for which any denominator is ZERO. Therefore it will NOT be necessary to show the excluded [or restrictions] values of the variables."
I know everyone is jumping for joy!!
Rule of Exponents for a Power of a Quotient
(a/b)m = am/bm
(x/3)3 = x3/27
(-c/2)2⋅4/3c
you must do the exponent portion first!!
c2/4⋅(4/3c)
c/3
Find the volume of a cube if each edge has length 6n/7 in
You just need to cube each factor
(6n/7)3 = 216n3/343 inches cubed
If you traveled for 7t/60 hours at 80r/9 mi/h, how far have you gone?
Just multiply
7t/60⋅80r/9
but simplify first and you get
28rt/27 miles
Math 6 Honors ( Periods 1, 2, & 3)
Prime Numbers & Composite Numbers 5-4
A prime number is one that has only two factors: 1 and the number itself, such as 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31...
A counting number that has more than two factors is called a composite number, such as 4, 6, 8, 9, 10...
Since one has exactly ONE factor, it is NEITHER PRIME NOR COMPOSITE!!
Zero is also NEITHER PRIME NOR COMPOSITE!!
Sieve of Eratosthenes - We did it!! :)
Every counting number greater than 1 has at least one prime factor -- which may be the number itself.
You can factor a number into PRIME FACTORS by using a factor tree or the inverted division, as shown in class.
Using the inverted division, you also start with the smallest prime number that is a factor... and work down
give the prime factors of 42
2⎣42
3⎣21
7
When we write 42 as 2⋅3⋅7 this product of prime factors is called the prime factorization of 42.
Two is the only even prime number because all the other even numbers have two as a factor.
Explain how you know that each of the following numbers must be composite...
111; 111,111; 111,111,111; and so on....
Using your divisibility rules you notice that the sums of the digits are multiples of 3.
List all the possible digits that can be the last digit of a prime number that is greater than 10.
1, 3, 7, 9.
Choose any six digit number such that the last three digits are a repeat of the first three digits. For example
652,652. You will find that 7, 11, and 13 are all factors of that number... no matter what number you choose... why is that???? email me your response.
A prime number is one that has only two factors: 1 and the number itself, such as 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31...
A counting number that has more than two factors is called a composite number, such as 4, 6, 8, 9, 10...
Since one has exactly ONE factor, it is NEITHER PRIME NOR COMPOSITE!!
Zero is also NEITHER PRIME NOR COMPOSITE!!
Sieve of Eratosthenes - We did it!! :)
Every counting number greater than 1 has at least one prime factor -- which may be the number itself.
You can factor a number into PRIME FACTORS by using a factor tree or the inverted division, as shown in class.
Using the inverted division, you also start with the smallest prime number that is a factor... and work down
give the prime factors of 42
2⎣42
3⎣21
7
When we write 42 as 2⋅3⋅7 this product of prime factors is called the prime factorization of 42.
Two is the only even prime number because all the other even numbers have two as a factor.
Explain how you know that each of the following numbers must be composite...
111; 111,111; 111,111,111; and so on....
Using your divisibility rules you notice that the sums of the digits are multiples of 3.
List all the possible digits that can be the last digit of a prime number that is greater than 10.
1, 3, 7, 9.
Choose any six digit number such that the last three digits are a repeat of the first three digits. For example
652,652. You will find that 7, 11, and 13 are all factors of that number... no matter what number you choose... why is that???? email me your response.
Math 6 Honors ( Periods 1, 2, & 3)
Prime Numbers and Composite Numbers 5-4
A prime number is a positive integer greater than 1 with exactly two factors, 1 and the number itself. The numbers 2, 3, 5, 7 are examples of prime numbers
A composite number is a positive integer greater than 1 with more than two factors. The numbers 4, 6, 8, 9, and 10 are examples of composite numbers.
Since 1 has exactly 1 factor, it is neither prime nor composite.
About 230 BCE Erathosthenes, a Greek Mathematician suggested a way to find prime numbers—up to a specific number. The method is called the Sieve of Eratosthenes because it picks out the prime numbers as a strainer, or sieve, picks out solid particles from a liquid.
You may factor a number into prime factors by using either of the following methods
➢ Inverted short division
➢ Factor tree
Both were shown in class.
Could you start the factor tree differently? If so, would you end up with the same answer?
The prime factors of 42 are the same in either factor tree, except for their order.
Every composite number greater than 1 can be written as a product of prime factors in exactly one way, except for the order of the factors.
When we write 42 as 2 ∙ 3 ∙ 7 this product is called the prime factorization of 42
Notice the order in which prime factorization is written.
Let’s try finding the prime factorization of 60
The prime factorization of 60 = 2 ∙ 2∙ 3 ∙ 5 or 22∙ 3∙ 5
A prime number is a positive integer greater than 1 with exactly two factors, 1 and the number itself. The numbers 2, 3, 5, 7 are examples of prime numbers
A composite number is a positive integer greater than 1 with more than two factors. The numbers 4, 6, 8, 9, and 10 are examples of composite numbers.
Since 1 has exactly 1 factor, it is neither prime nor composite.
About 230 BCE Erathosthenes, a Greek Mathematician suggested a way to find prime numbers—up to a specific number. The method is called the Sieve of Eratosthenes because it picks out the prime numbers as a strainer, or sieve, picks out solid particles from a liquid.
You may factor a number into prime factors by using either of the following methods
➢ Inverted short division
➢ Factor tree
Both were shown in class.
Could you start the factor tree differently? If so, would you end up with the same answer?
The prime factors of 42 are the same in either factor tree, except for their order.
Every composite number greater than 1 can be written as a product of prime factors in exactly one way, except for the order of the factors.
When we write 42 as 2 ∙ 3 ∙ 7 this product is called the prime factorization of 42
Notice the order in which prime factorization is written.
Let’s try finding the prime factorization of 60
The prime factorization of 60 = 2 ∙ 2∙ 3 ∙ 5 or 22∙ 3∙ 5
Tuesday, November 29, 2011
Math 6 Honors ( Periods 1, 2, & 3)
Square Numbers and Square Roots 5-3
Numbers such as 1, 4, 9, 16, 25, 36, 49... are called square numbers or PERFECT SQUARES.
One of two EQUAL factors of a square is called the square root of the number. To denote a square root of a number we use a radical sign (looks like a check mark with an extension) See our textbook page 157.
Although we use a radical sign to denote cube roots, fourth roots and more, without a small number on the radical sign, we have come to call that the square root.
SQRT = stands for square root, since this blog will not let me use the proper symbol) √ is the closest to the symbol
so the SQRT of 25 is 5. Actually 5 is the principal square root. Since 5 X 5 = 25
There is another root because
(-5)(-5) = 25 but in this class we are primarily interested in the principal square root or the positive square root.
Evaluate the following:
SQRT 36 + SQRT 64 = 6 + 8 = 14
SQRT 100 = 10
Is it true that SQRT 36 + SQRT 64 = SQRT 100? No
You cannot add square roots in that manner.
However look at the following:
Evaluate
SQRT 225 = 15
(SQRT 9)(SQRT 25)= (3)(5) = 15
so
SQRT 225 = (SQRT 9)(SQRT 25)
Also notice that the SQRT 1600 = 40
But notice that SQRT 1600 = SQRT (16)(100) = 4(10) = 40
Try this:
Take an odd perfect square, such as 9. Square the largest whole number that is less than half of it. ( For 9 this would be 4). If you add this square to the original number what kind of number do you get? Try it with other odd perfect squares...
In this case, 9 + 16 = 25... hmmm... what's 25???
Numbers such as 1, 4, 9, 16, 25, 36, 49... are called square numbers or PERFECT SQUARES.
One of two EQUAL factors of a square is called the square root of the number. To denote a square root of a number we use a radical sign (looks like a check mark with an extension) See our textbook page 157.
Although we use a radical sign to denote cube roots, fourth roots and more, without a small number on the radical sign, we have come to call that the square root.
SQRT = stands for square root, since this blog will not let me use the proper symbol) √ is the closest to the symbol
so the SQRT of 25 is 5. Actually 5 is the principal square root. Since 5 X 5 = 25
There is another root because
(-5)(-5) = 25 but in this class we are primarily interested in the principal square root or the positive square root.
Evaluate the following:
SQRT 36 + SQRT 64 = 6 + 8 = 14
SQRT 100 = 10
Is it true that SQRT 36 + SQRT 64 = SQRT 100? No
You cannot add square roots in that manner.
However look at the following:
Evaluate
SQRT 225 = 15
(SQRT 9)(SQRT 25)= (3)(5) = 15
so
SQRT 225 = (SQRT 9)(SQRT 25)
Also notice that the SQRT 1600 = 40
But notice that SQRT 1600 = SQRT (16)(100) = 4(10) = 40
Try this:
Take an odd perfect square, such as 9. Square the largest whole number that is less than half of it. ( For 9 this would be 4). If you add this square to the original number what kind of number do you get? Try it with other odd perfect squares...
In this case, 9 + 16 = 25... hmmm... what's 25???
Wednesday, November 16, 2011
Math 6 Honors ( Periods 1, 2, & 3)
Tests for Divisibility 5-2
It is important to learn the following divisibility rules:
A number is divisibility by:
2 ... if the ones digit of the number is even
3 ... if the sum of the digits is divisible by three ( add the digits together)
4 ... if the number formed by the last two digits is divisible by by four ( Just LOOK at the last two numbers-- DON"T ADD them!!)
5 ... if the ones digits of the number is a 5 or a 0
6 ... if the number is divisible by both 2 and 3... (or if it is even and divisible by 3)
8 ... if the number formed by the last three digits is divisible by 8. (Like FOUR, just look at the last three digits-- divide them by 8)
9 ... if the sum of the digits is divisible by 9
10 ... if the ones digits of the number is a 0.
You will not need to know the divisibility rules for 7 or 11 but they are interesting...
You can test for divisibility by 7
Let's start with a number 959
Step 1: drop the one's digit so we have 95
Step 2: Subtract twice the ones' digit ( that you dropped) in this case we dropped a 9
so we double that and subtract 18 from 95
or 95-18 = 77. If the results, in the case, 77, is divisible by 7 --- so is the original number 959.
Step 3: If the number you get is still to big.. continue the process until you can determine if your number is divisible by 7.
To test for divisibility by 11
add the alternative digits beginning with the first
so let's try the following
4,378,396
Step 1: Add the alternate digits beginning with the 1st 4 + 7+ 3 + 6 = 20
Step 2: Add alternate digits beginning with the 2nd 3 + 8 + 9 = 20
Step 3: If the difference of the sums is divisible by 11 so is the original number.
In this case, 20-20 = 0 and 0/11= 0 so
4,378,396 is divisible by 11.
A good test for divisibility by 25 would be if the last two digits represent a multiple of 25.
A perfect number is one that is the SUM of all its factors except itself. The smallest perfect number is 6, since 6 = 1 + 2+ 3
The next perfect number is 28 since
28 = 1 + 2 + 4 + 7 + 14
What is the next perfect number?
It is important to learn the following divisibility rules:
A number is divisibility by:
2 ... if the ones digit of the number is even
3 ... if the sum of the digits is divisible by three ( add the digits together)
4 ... if the number formed by the last two digits is divisible by by four ( Just LOOK at the last two numbers-- DON"T ADD them!!)
5 ... if the ones digits of the number is a 5 or a 0
6 ... if the number is divisible by both 2 and 3... (or if it is even and divisible by 3)
8 ... if the number formed by the last three digits is divisible by 8. (Like FOUR, just look at the last three digits-- divide them by 8)
9 ... if the sum of the digits is divisible by 9
10 ... if the ones digits of the number is a 0.
You will not need to know the divisibility rules for 7 or 11 but they are interesting...
You can test for divisibility by 7
Let's start with a number 959
Step 1: drop the one's digit so we have 95
Step 2: Subtract twice the ones' digit ( that you dropped) in this case we dropped a 9
so we double that and subtract 18 from 95
or 95-18 = 77. If the results, in the case, 77, is divisible by 7 --- so is the original number 959.
Step 3: If the number you get is still to big.. continue the process until you can determine if your number is divisible by 7.
To test for divisibility by 11
add the alternative digits beginning with the first
so let's try the following
4,378,396
Step 1: Add the alternate digits beginning with the 1st 4 + 7+ 3 + 6 = 20
Step 2: Add alternate digits beginning with the 2nd 3 + 8 + 9 = 20
Step 3: If the difference of the sums is divisible by 11 so is the original number.
In this case, 20-20 = 0 and 0/11= 0 so
4,378,396 is divisible by 11.
A good test for divisibility by 25 would be if the last two digits represent a multiple of 25.
A perfect number is one that is the SUM of all its factors except itself. The smallest perfect number is 6, since 6 = 1 + 2+ 3
The next perfect number is 28 since
28 = 1 + 2 + 4 + 7 + 14
What is the next perfect number?
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